Question 1 (Multiple Choice Worth 1 points)Choose all of the following equations that have a vertex that is the maximum point of the parabola. More than one answer may be chosen. y = −4x2 + 8x − 19 y = −x2 − 7x + 1 y = 8x2 − 6x + 128 y = 3x2 + 9x − 4 --------------------------------------… Question 2 (Multiple Choice Worth 1 points)Find the vertex of the quadratic equation: y = 2x2 + 12x − 4. (−3, 50) (3, 50) (−3, −22) (−3, −58) --------------------------------------… Question 3 (Multiple Choice Worth 1 points)When the quadratic equation y = (x − 3)(4x + 2) is written in standard form, what is the value of the coefficient "b?" 1 4 −10 −6 --------------------------------------…Question 4 (Multiple Choice Worth 1 points)Choose all of the following equations that have a graph in which the parabola opens downward. More than one answer may be chosen. y = 2x2 + 2x + 8 y = −4x2 + 8x − 19 y = 16x2 + 2x − 4 y = −x2 − 6x + 10 --------------------------------------… Question 5 (Multiple Choice Worth 1 points)Choose the equation below that corresponds to the graph shown. y = −3x2 − 12x − 14 y = 3x2 + 12x − 14 y = −3x2 + 12x − 14 y = 3x2 − 12x − 14 --------------------------------------… Question 6 (Multiple Choice Worth 1 points)A quadratic equation has an x-squared term, an x term and a constant term. Sometimes Always Never --------------------------------------…Question 7 (Essay Worth 4 points)Compare and contrast the two quadratic equations below. In order to receive full credit, use complete sentences to describe the following:The direction each parabola opens The vertex of each parabolay = x2 − 2xy = −2x2 + 4x − 3

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Q1: Both answers A and B because they both are negative, meaning that they both open downwards. Because of this, they both have vertexes that are the highest point of the parabola.Q2: All you have to do is factor the equation. Because they are not factorable without using complex numbers, this means that it doesn’t cross the X axis. This automatically out-rules the last two. The first one is out ruled because if you input the x coordinate, it doesn’t equal 50 (y coordinate).Q3: (x − 3)(4x + 2) factor them out and you get y=4×2+2x-12x-6 or y=4×2-10x-6 the b term is -6Q4: Both the second and the fourth equations open downwards because they have a negative in front of the leading term. Easy as that.Q5: There is no graph providedQ6: Always! The x squared term is what makes it a parabola and not another function. Even if the equation is y=X2 for instance. The x2 is the x-squared term. the x term is not present, meaning that it is 0x. The constant term is also 0 because it isn’t there either. The true equation (with all terms included) would be y=x2+0x+0Q7: The first equation opens upwards because the leading term is positive as opposed to the second which is negative. The first equation also has a minimum because it opens upwards (meaning it keeps going on and on forever in the upwards direction from it’s vertex). The second one has a maximum because it opens downwards (meaning it keeps going on and on forever in the downwards direction away from it’s vertex)Hope this helped!