If 35.8 g Mg react with 82.3 g HCl according to the reaction below, how many grams of hydrogen gas is made?





If 35.8 g Mg react with 82.3 g HCl according to the reaction below, how many grams of hydrogen gas will be produced, and how many grams of the excess reactant will be left over?Unbalanced equation: Mg + HCl → MgCl2 + H2Be sure to show all of your work.Question 2 (Essay Worth 5 points)If 4.2 moles of copper metal reacts with 6.3 moles of silver nitrate, how many moles of silver metal can be formed, and how many moles of the excess reactant will be left over when the reaction is complete?Unbalanced equation: Cu + AgNO3 → Cu(NO3)2 + AgBe sure to show all of your work.Question 3 (Multiple Choice Worth 3 points)If 2.0 moles of A and 5.0 moles of B react according to the hypothetical reaction below, how many moles of the excess reactant will be left over at the end of the reaction?A + 2B → AB20.50 mol A left over0.50 mol B left over1.0 mol A left over1.0 mol B left overQuestion 4 (Essay Worth 5 points)If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the excess reactant will be left over when the reaction is complete?Be sure to write out the balanced equation for this reaction and to show all of your work.Question 5 (Multiple Choice Worth 2 points)When 6.0 mol H2O react with 5.0 mol Al in the reaction below, 4.0 mol of Al are used up in the reaction. How many moles of Al are left over unreacted?2 Al + 3 H2O → Al2O3 + 3H22.5 mol Al left over2.0 mol Al left over1.0 mol Al left over0.5 mol Al left over



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  • If 2 0 moles of A and 3 0 moles of B react according to the hypothetical reaction below how many moles of the excess reactant will be left over at the end of the reaction?A 2B → AB2




One Answer to “If 35.8 g Mg react with 82.3 g HCl according to the reaction below, how many grams of hydrogen gas is made?”

  1. undupable says:

    Mg + 2 HCl → MgCl2 + H2(35.8 g Mg) / (24.3051 g Mg/mol) = 1.4729 mol Mg(82.3 g HCl) / (36.4611 g HCl/mol) = 2.2572 mol HCl2.2572 mole of HCl would react completely with 2.2572 x (1/2) = 1.1286 mole of Mg, but there is more Mg present than that, so Mg is in excess and HCl is the limiting reactant.(2.2572 mol HCl) x (1/2) x ( 2.0159 g H2/mol) = 2.28 g H2